2x^2-16x+32=200

Solution for 2x^2-16x+32=200 equation:

2x^2-16x+32=200

We move all terms to the left:

2x^2-16x+32-(200)=0

We add all the numbers together, and all the variables

2x^2-16x-168=0

a = 2; b = -16; c = -168;
Δ = b2-4ac
Δ = -162-4·2·(-168)
Δ = 1600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1600}=40$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-40}{2*2}=\frac{-24}{4}
=-6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+40}{2*2}=\frac{56}{4}
=14
$